Functions CMAT Old Questions
The set of all points (e , e-2) where e is a real number is the graph of y = [2014]
1/e2
e2
te1/11
ln(1)
If the function f(x) is defined by f(x) = x5 - 1 then the inverse function of f is defined by f(x)[2014]
5√(x-1)
5√(x+1)
√(x-1)
√(x+1)
Three Solutions of the equation f(x) = 0 are -2,0 and 3. Therefore the three solutions of the equations f(x-2)=0 are[2014]
-4,-2 and 1
-2, 0 and 3
4,2 and 5
0,2 and 5
The functional relationship of the data given below is equal to[2009]
X: | 1 | 2 | 3 | 4 | 5 |
Y: | 1 | 3 | 5 | 7 | 9 |
y = 2x - 1
y = 2x + 1
y = 3x - 2
y = 3x - 1